(A) Total work done by $P$ in terms of hours = $12 \times 8 = 96$ hours.Total work done by $Q$ in terms of hours = $8 \times 10 = 80$ hours.Work done

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(A) Total work done by $P$ in terms of hours = $12 \times 8 = 96$ hours.Total work done by $Q$ in terms of hours = $8 \times 10 = 80$ hours.Work done by $P$ in $1$ hour = $\frac{1}{96}$.Work done by $Q$ in $1$ hour = $\frac{1}{80}$.Combined work done by $P$ and $Q$ in $1$ hour = $\frac{1}{96} + \frac{1}{80} = \frac{5 + 6}{480} = \frac{11}{480}$.If they work together for $8$ hours a day,the work done per day = $8 \times \frac{11}{480} = \frac{11}{60}$.Let the number of days be $x$. Then,$x \times \frac{11}{60} = 1$.$x = \frac{60}{11} = 5 \frac{5}{11}$ days.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

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$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

A
$5 \frac{5}{11}$
B
$5 \frac{6}{11}$
C
$6 \frac{5}{11}$
D
$6 \frac{6}{11}$

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Time and Work and Wages

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Time and Work

$A$ and $B$ together can complete a work in $8$ days. $B$ alone can complete that work in $12$ days. $B$ alone worked for $4$ days. After that,how long will $A$ alone take to complete the remaining work?

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$A$ can do a work in $5 \, \text{days}$ less than the time taken by $B$ to do it. If both of them together take $11 \frac{1}{9} \, \text{days}$, then the time taken by $B$ alone to do the same work (in $\text{days}$) is

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$A$ can do a piece of work in $12$ days and $B$ in $15$ days. They work together for $5$ days and then $B$ leaves. The number of days taken by $A$ to finish the remaining work is:

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$A$ and $B$ can separately complete a piece of work in $20$ days and $30$ days respectively. They worked together for some time,then $B$ left the work. If $A$ completed the rest of the work in $10$ days,then for how many days did $B$ work?

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Two workers $A$ and $B$ working together completed a job in $5$ days. If $A$ worked twice as efficiently as he actually did and $B$ worked $\frac{1}{3}$ as efficiently as he actually did,the work would have completed in $3$ days. Find the time for $A$ to complete the job alone (in days).

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$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

Similar Questions

$A$ and $B$ together can complete a work in $8$ days. $B$ alone can complete that work in $12$ days. $B$ alone worked for $4$ days. After that,how long will $A$ alone take to complete the remaining work?

$A$ can do a work in $5 \, \text{days}$ less than the time taken by $B$ to do it. If both of them together take $11 \frac{1}{9} \, \text{days}$, then the time taken by $B$ alone to do the same work (in $\text{days}$) is

$A$ can do a piece of work in $12$ days and $B$ in $15$ days. They work together for $5$ days and then $B$ leaves. The number of days taken by $A$ to finish the remaining work is:

$A$ and $B$ can separately complete a piece of work in $20$ days and $30$ days respectively. They worked together for some time,then $B$ left the work. If $A$ completed the rest of the work in $10$ days,then for how many days did $B$ work?

Two workers $A$ and $B$ working together completed a job in $5$ days. If $A$ worked twice as efficiently as he actually did and $B$ worked $\frac{1}{3}$ as efficiently as he actually did,the work would have completed in $3$ days. Find the time for $A$ to complete the job alone (in days).

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