(A) Work done by $A$ in $5$ days $= \frac{5}{40} = \frac{1}{8}$.Remaining work $= 1 - \frac{1}{8} = \frac{7}{8}$.$B$ completes $\frac{7}{8}$ of the wo

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(A) Work done by $A$ in $5$ days $= \frac{5}{40} = \frac{1}{8}$.Remaining work $= 1 - \frac{1}{8} = \frac{7}{8}$.$B$ completes $\frac{7}{8}$ of the work in $21$ days.Therefore,$B$ would complete the whole work in $\frac{21 \times 8}{7} = 24$ days.Now,$A$ takes $40$ days and $B$ takes $24$ days to complete the work individually.Working together,$A$ and $B$ would complete the work in $\frac{x \times y}{x + y}$ days,where $x = 40$ and $y = 24$.Time taken $= \frac{40 \times 24}{40 + 24} = \frac{960}{64} = 15$ days.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Difficult

$A$ can complete a piece of work in $40$ days. He starts working,but having some other engagements,he leaves after $5$ days. Thereafter,$B$ completes the remaining work in $21$ days. How many days would $A$ and $B$ take to complete this work working together?

A
$15$
B
$16$
C
$17$
D
$11$

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Time and Work and Wages

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Time and Work

$10$ men can complete a piece of work in $15$ days and $15$ women can complete the same work in $12$ days. If all the $10$ men and $15$ women work together,in how many days will the work be completed?

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$A$ and $B$ can do a job in $6$ and $12$ days,respectively. They began the work together,but $A$ leaves after $3$ days. Then,the total number of days needed for the completion of the work is:

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$A$ takes $10\, \text{days}$ less than the time taken by $B$ to finish a piece of work. If both $A$ and $B$ can do it in $12\, \text{days}$, then the time taken by $B$ alone to finish the work is (in $\text{days}$)

Medium

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$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

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$10$ men can cut $15$ trees in $2$ hours. If $2$ men leave the job,how many trees will be cut in $3$ hours?

Easy

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$A$ can complete a piece of work in $40$ days. He starts working,but having some other engagements,he leaves after $5$ days. Thereafter,$B$ completes the remaining work in $21$ days. How many days would $A$ and $B$ take to complete this work working together?

Similar Questions

$10$ men can complete a piece of work in $15$ days and $15$ women can complete the same work in $12$ days. If all the $10$ men and $15$ women work together,in how many days will the work be completed?

$A$ and $B$ can do a job in $6$ and $12$ days,respectively. They began the work together,but $A$ leaves after $3$ days. Then,the total number of days needed for the completion of the work is:

$A$ takes $10\, \text{days}$ less than the time taken by $B$ to finish a piece of work. If both $A$ and $B$ can do it in $12\, \text{days}$, then the time taken by $B$ alone to finish the work is (in $\text{days}$)

$P$ can complete a work in $12$ days working $8$ hours a day. $Q$ can complete the same work in $8$ days working $10$ hours a day. If both $P$ and $Q$ work together,working $8$ hours a day,in how many days can they complete the work?

$10$ men can cut $15$ trees in $2$ hours. If $2$ men leave the job,how many trees will be cut in $3$ hours?

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