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(C) To find who completes the work first,we calculate the total time taken by each person to complete $1$ full unit of work:For $P$: $\frac{1}{4}$ of

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$R$

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(C) To find who completes the work first,we calculate the total time taken by each person to complete $1$ full unit of work:For $P$: $\frac{1}{4}$ of the work is done in $10$ days. Therefore,the total time taken by $P = 10 	imes 4 = 40$ days.For $Q$: $40\%$ (or $\frac{40}{100} = \frac{2}{5}$) of the work is done in $40$ days. Therefore,the total time taken by $Q = 40 	imes \frac{5}{2} = 100$ days.For $R$: $\frac{1}{3}$ of the work is done in $13$ days. Therefore,the total time taken by $R = 13 	imes 3 = 39$ days.Comparing the total time taken: $P = 40$ days,$Q = 100$ days,and $R = 39$ days.Since $39 < 40 < 100$,$R$ will complete the work first.

$P$ can do $\left(\frac{1}{4}\right)$ of the work in $10$ days. $Q$ can do $40\%$ of the work in $40$ days and $R$ can do $\left(\frac{1}{3}\right)$ of the work in $13$ days. Who will complete the work first?

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