(B) Let the time taken by $(B+C)$ be $x$ days. Then,the time taken by $A$ is $3x$ days.Therefore,the work done by $(A+B+C)$ in $1$ day is $\frac{1}{3x

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(B) Let the time taken by $(B+C)$ be $x$ days. Then,the time taken by $A$ is $3x$ days.Therefore,the work done by $(A+B+C)$ in $1$ day is $\frac{1}{3x} + \frac{1}{x} = \frac{1+3}{3x} = \frac{4}{3x}$.Given that $(A+B+C)$ complete the work in $24$ days,so $\frac{4}{3x} = \frac{1}{24}$.$3x = 4 \times 24 = 96$,so $x = 32$ days.Thus,$A$ takes $3x = 3 \times 32 = 96$ days to finish the job alone.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$A$ takes three times as long as $B$ and $C$ together to do a job. $B$ takes four times as long as $A$ and $C$ together to do the work. If all the three,working together,can complete the job in $24$ days,then the number of days $A$ alone will take to finish the job is:

A
$100$
B
$96$
C
$95$
D
$90$

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Time and Work and Wages

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Time and Work

$A$ can finish a work in $24$ days,$B$ in $9$ days and $C$ in $12$ days. $B$ and $C$ start the work but are forced to leave after $3$ days. The remaining work was done by $A$ in (in days):

Medium

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$3$ women and $18$ children together take $2$ days to complete a piece of work. How many days will $9$ children alone take to complete the piece of work,if $6$ women alone can complete the piece of work in $3$ days?

Medium

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$A$ does half as much work as $B$ in $\frac{3}{4}$ of the time. If together they take $18$ days to complete a work,then how much time shall $B$ take to complete it? (in days)

Medium

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$A$ and $B$ can do a piece of work in $10$ days. $B$ and $C$ can do it in $12$ days. $A$ and $C$ can do it in $15$ days. How long will $A$ take to do it alone? (in days)

Easy

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$20$ men can complete a piece of work in $16$ days. After $5$ days from the start of the work,some men left. If the remaining work was completed by the remaining men in $18 \frac{1}{3}$ days,how many men left after $5$ days from the start of the work?

Easy

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$A$ takes three times as long as $B$ and $C$ together to do a job. $B$ takes four times as long as $A$ and $C$ together to do the work. If all the three,working together,can complete the job in $24$ days,then the number of days $A$ alone will take to finish the job is:

Similar Questions

$A$ can finish a work in $24$ days,$B$ in $9$ days and $C$ in $12$ days. $B$ and $C$ start the work but are forced to leave after $3$ days. The remaining work was done by $A$ in (in days):

$3$ women and $18$ children together take $2$ days to complete a piece of work. How many days will $9$ children alone take to complete the piece of work,if $6$ women alone can complete the piece of work in $3$ days?

$A$ does half as much work as $B$ in $\frac{3}{4}$ of the time. If together they take $18$ days to complete a work,then how much time shall $B$ take to complete it? (in days)

$A$ and $B$ can do a piece of work in $10$ days. $B$ and $C$ can do it in $12$ days. $A$ and $C$ can do it in $15$ days. How long will $A$ take to do it alone? (in days)

$20$ men can complete a piece of work in $16$ days. After $5$ days from the start of the work,some men left. If the remaining work was completed by the remaining men in $18 \frac{1}{3}$ days,how many men left after $5$ days from the start of the work?

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