2, cm of rain has fallen on a 1, km^2 of land | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Total volume of rain water = Area $	imes$ height.Given,Area = $1\, km^2 = (1000\, m)^2 = 1,000,000\, m^2$.Height = $2\, cm = 0.02\, m$.Total volu

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) Total volume of rain water = Area $	imes$ height.Given,Area = $1\, km^2 = (1000\, m)^2 = 1,000,000\, m^2$.Height = $2\, cm = 0.02\, m$.Total volume = $1,000,000\, m^2 	imes 0.02\, m = 20,000\, m^3$.Volume of collected water = $50\%$ of $20,000\, m^3 = 0.5 	imes 20,000 = 10,000\, m^3$.Base area of the pool = $100\, m 	imes 10\, m = 1,000\, m^2$.Increase in water level = $\frac{	ext{Volume collected}}{	ext{Base area of pool}} = \frac{10,000\, m^3}{1,000\, m^2} = 10\, m$.Therefore,the water level in the pool would have increased by $10\, m$.

$2\, cm$ of rain has fallen on a $1\, km^2$ of land. Assuming that $50\%$ of the raindrops could have been collected and contained in a pool having a $100\, m \times 10\, m$ base,by what level would the water level in the pool have increased? (in $m$)

Similar Questions

$A$ cube of edge $3\, cm$ of iron weighs $12\, gm$. What is the weight of a similar cube of iron whose edge is $12\, cm$? (in $gm$)

The base of a right prism is an equilateral triangle with a side of $6 \, cm$. If the volume of the prism is $108 \sqrt{3} \, cm^3$,its height is ...... $cm$.

The curved surface area of a circular cylinder of height $h$ and the slant surface area of a cone of slant height $2h$,having the same circular base,are in the ratio of:

If the surface area of a sphere is $346.5 \, cm^{2},$ then its radius is.......$cm$
$\left[\text{taking } \pi = \frac{22}{7}\right]$

Volume of the cylinder is $1650\, m^3$,whereas the surface area of its base is $78 \frac{4}{7}\, m^2$. Find out the height of the cylinder (in $m$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module