$958 \times 21 \div 4 = ?$

$A$ number is of two digits. The position of digits is interchanged and the new number is added to the original number. The resultant number will always be divisible by

The sum of squares of two numbers is $68$ and the square of their difference is $36$. The product of the two numbers is

Find the least number which when divided by $12, 18, 36$ and $45$ leaves the remainder $8, 14, 32$ and $41$ respectively.

$8000 \div 16 - 200 = ? \times 6$

$A$ fraction becomes $4$ when $1$ is added to both the numerator and denominator; and it becomes $7$ when $1$ is subtracted from both the numerator and denominator. The numerator of the given fraction is