$(\sqrt{4489}-\sqrt{2601})=(?)^{2}$

If a number is multiplied by $\frac{3}{5}$ of itself,the value so obtained is $3^{2}$ less than $12^{2}$. What is $\frac{5}{3}$ of that number?

$(0.83 \times 0.83 \times 0.83 + 0.17 \times 0.17 \times 0.17)$ is equal to ...........

Simplify $\frac{(0.9743)^{3}-(0.0257)^{3}}{(0.9743)^{2}+(0.9743)(0.0257)+(0.0257)^{2}}$

$40.005 \%$ of $439.998 + ? \%$ of $655.011 = 228.5$

The difference between one-fourth of a number and one-seventh of the same number is $24$. What is the number?