left[(72)^{2} div 36+(?)^{2}right] div 5=45 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the missing number be $x$.Given equation: $[(72)^{2} \div 36 + x^{2}] \div 5 = 45$Step $1$: Multiply both sides by $5$:$(72)^{2} \div 36 + x^{

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(A) Let the missing number be $x$.Given equation: $[(72)^{2} \div 36 + x^{2}] \div 5 = 45$Step $1$: Multiply both sides by $5$:$(72)^{2} \div 36 + x^{2} = 45 	imes 5$$(72)^{2} \div 36 + x^{2} = 225$Step $2$: Simplify $(72)^{2} \div 36$:$(5184) \div 36 + x^{2} = 225$$144 + x^{2} = 225$Step $3$: Solve for $x^{2}$:$x^{2} = 225 - 144$$x^{2} = 81$Step $4$: Find $x$:$x = \sqrt{81} = 9$Therefore,the missing number is $9$.

$\left[(72)^{2} \div 36+(?)^{2}\right] \div 5=45$

Similar Questions

$9999 + 8888 + 777 + ? = 19700$

$69.69 - 51.54 + 73.64 = ? + 32.42$

The sum of the first $45$ natural numbers is:

$A$ number exceeds $20 \%$ of itself by $40$. The number is:

$(0.88 \times 880 \div 8) \times 6 = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module