The sum of the first $45$ natural numbers is:

The ten's digit of a two-digit number is greater than the unit's digit by $7$. If we subtract $63$ from the number,the new number obtained is formed by interchanging the digits. Find the number.

The number of times $79$ must be subtracted from $50000$ so that the remainder is $43759$ is:

If $30 \%$ of a number is $190.8$,what will be $175 \%$ of that number?

$25 \%$ of $48 + 50 \%$ of $120 = ? \%$ of $1200$

$90 \times \frac{6}{18} + 73 = ?$