(90 + 91 + 92 + ldots + 110) is equal to | vedclass

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Question

(A) The given series is an arithmetic progression where the first term $a = 90$,the last term $l = 110$,and the number of terms $n$ is calculated as $

Vedclass · Accepted Answer

$2100$

Vedclass · Answer

(A) The given series is an arithmetic progression where the first term $a = 90$,the last term $l = 110$,and the number of terms $n$ is calculated as $n = (110 - 90) + 1 = 21$.The sum of an arithmetic progression is given by the formula $S_n = \frac{n}{2}(a + l)$.Substituting the values: $S_{21} = \frac{21}{2}(90 + 110)$.$S_{21} = \frac{21}{2}(200)$.$S_{21} = 21 	imes 100 = 2100$.

$(90 + 91 + 92 + \ldots + 110)$ is equal to

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