11111_{2} + 10001_{2} + 1011_{2} = ? | vedclass

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(C) To add the binary numbers,we perform column-wise addition:$11111_{2} = 31_{10}$$10001_{2} = 17_{10}$$1011_{2} = 11_{10}$Sum in decimal: $31 + 17 +

Vedclass · Accepted Answer

$111011_{2}$

Vedclass · Answer

(C) To add the binary numbers,we perform column-wise addition:$11111_{2} = 31_{10}$$10001_{2} = 17_{10}$$1011_{2} = 11_{10}$Sum in decimal: $31 + 17 + 11 = 59_{10}$Now,convert $59_{10}$ to binary:$59 \div 2 = 29$ remainder $1$$29 \div 2 = 14$ remainder $1$$14 \div 2 = 7$ remainder $0$$7 \div 2 = 3$ remainder $1$$3 \div 2 = 1$ remainder $1$$1 \div 2 = 0$ remainder $1$Reading remainders from bottom to top,we get $111011_{2}$.Alternatively,adding column-wise:$11111 + 10001 + 01011 = 111011_{2}$.

$11111_{2} + 10001_{2} + 1011_{2} = ?$

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