frac{sqrt{5}-sqrt{3}}{sqrt{5}+sqrt{3}} is equ | vedclass

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(B) To simplify the expression,we rationalize the denominator by multiplying the numerator and the denominator by the conjugate of the denominator,whi

Vedclass · Accepted Answer

$4-\sqrt{15}$

Vedclass · Answer

(B) To simplify the expression,we rationalize the denominator by multiplying the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{5}-\sqrt{3})$.$\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}} 	imes \frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}-\sqrt{3}}$$= \frac{(\sqrt{5}-\sqrt{3})^2}{(\sqrt{5})^2-(\sqrt{3})^2}$$= \frac{5 + 3 - 2\sqrt{15}}{5-3}$$= \frac{8 - 2\sqrt{15}}{2}$$= \frac{2(4 - \sqrt{15})}{2} = 4 - \sqrt{15}$

$\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}$ is equal to

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