2-chlorobutane is heated with alcoholic NaOH. | vedclass

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Question

(C) The reaction of $2-$chlorobutane with alcoholic $NaOH$ is a dehydrohalogenation reaction,which follows $Saytzeff$ rule.According to $Saytzeff$ rul

Vedclass · Accepted Answer

$2-$Butene

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(C) The reaction of $2-$chlorobutane with alcoholic $NaOH$ is a dehydrohalogenation reaction,which follows $Saytzeff$ rule.According to $Saytzeff$ rule,the more substituted alkene is the major product.$CH_3-CH_2-CH(Cl)-CH_3 \xrightarrow{alc. NaOH} CH_3-CH=CH-CH_3$ ($2-$Butene,major product) + $CH_3-CH_2-CH=CH_2$ ($1-$Butene,minor product).Thus,$2-$Butene is formed in a larger amount.

$2-$chlorobutane is heated with alcoholic $NaOH$. The product formed in larger amount is:

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