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Question

(C) We know that $\cot x = \frac{\cos x}{\sin x}$ and $	an x = \frac{\sin x}{\cos x}$.Substituting these into the expression: $\cot x - 	an x = \fra

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$2\cot 2x$

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(C) We know that $\cot x = \frac{\cos x}{\sin x}$ and $	an x = \frac{\sin x}{\cos x}$.Substituting these into the expression: $\cot x - 	an x = \frac{\cos x}{\sin x} - \frac{\sin x}{\cos x}$.Taking the common denominator: $\frac{\cos^2 x - \sin^2 x}{\sin x \cos x}$.Using the identity $\cos^2 x - \sin^2 x = \cos 2x$ and multiplying the numerator and denominator by $2$: $\frac{2 \cos 2x}{2 \sin x \cos x}$.Since $2 \sin x \cos x = \sin 2x$,the expression becomes $\frac{2 \cos 2x}{\sin 2x} = 2 \cot 2x$.

$\cot x - \tan x = $

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