sin {163^circ} cos {347^circ} + sin {73^circ} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $\sin {163^\circ} \cos {347^\circ} + \sin {73^\circ} \sin {167^\circ}$Using the reduction formulas:$\sin {163^\circ} = \sin (180

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(B) Given expression: $\sin {163^\circ} \cos {347^\circ} + \sin {73^\circ} \sin {167^\circ}$Using the reduction formulas:$\sin {163^\circ} = \sin (180^\circ - 17^\circ) = \sin {17^\circ}$$\cos {347^\circ} = \cos (360^\circ - 13^\circ) = \cos {13^\circ}$$\sin {73^\circ} = \cos (90^\circ - 73^\circ) = \cos {17^\circ}$$\sin {167^\circ} = \sin (180^\circ - 13^\circ) = \sin {13^\circ}$Substituting these values into the expression:$= \sin {17^\circ} \cos {13^\circ} + \cos {17^\circ} \sin {13^\circ}$Using the identity $\sin (A + B) = \sin A \cos B + \cos A \sin B$:$= \sin (17^\circ + 13^\circ) = \sin {30^\circ}$Since $\sin {30^\circ} = 1/2$,the final answer is $1/2$.

$\sin {163^\circ} \cos {347^\circ} + \sin {73^\circ} \sin {167^\circ} = $

Similar Questions

If $\tan \left( \frac{\pi}{4} + \theta \right) + \tan \left( \frac{\pi}{4} - \theta \right) = \lambda \sec 2\theta$,then $\lambda$ =

If $\theta$ is an acute angle and $\tan(4\theta - 50^{\circ}) = \cot(50^{circ} - \theta)$,then the value of $\theta$ in degrees is:

The value of $\frac{\sin ^{3} A+\cos ^{3} A}{\sin A+\cos A}+\frac{\cos ^{3} A-\sin ^{3} A}{\cos A-\sin A}$ is

Let $f$ be an odd function defined on the set of real numbers such that for $x \geq 0$,$f(x) = 3 \sin x + 4 \cos x$. Then $f(x)$ at $x = -\frac{11\pi}{6}$ is equal to:

The value of $\cot \frac{\pi}{20} \cot \frac{3 \pi}{20} \cot \frac{5 \pi}{20} \cot \frac{7 \pi}{20} \cot \frac{9 \pi}{20}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module