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(D) Let the $6$ chairs be numbered $1$ to $6$ in a circle.Since $C$ is opposite to $D$,let $D$ be at position $1$ and $C$ be at position $4$.$A$ is be

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$B$ and $E$ are neighbours

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(D) Let the $6$ chairs be numbered $1$ to $6$ in a circle.Since $C$ is opposite to $D$,let $D$ be at position $1$ and $C$ be at position $4$.$A$ is between $D$ and $F$. Since $D$ is at $1$,$A$ must be at $2$ and $F$ must be at $3$ (or vice versa,but $A$ must be adjacent to $D$).If $A$ is at $2$ and $F$ is at $3$,then $D$ is at $1$,$A$ is at $2$,$F$ is at $3$,$C$ is at $4$.The remaining positions are $5$ and $6$ for $B$ and $E$.Condition $3$ states $D$ and $E$ are not neighbours. $D$ is at $1$,so $E$ cannot be at $6$ or $2$. Since $A$ is at $2$,$E$ must be at $5$.This leaves $B$ at position $6$.Arrangement: $1:D, 2:A, 3:F, 4:C, 5:E, 6:B$.Checking the options:$A$ is opposite to $B$ ($2$ and $6$ - False).$D$ is opposite to $E$ ($1$ and $5$ - False).$C$ and $B$ are neighbours ($4$ and $6$ - False).$B$ and $E$ are neighbours ($6$ and $5$ - True).Thus,$B$ and $E$ must be neighbours.

$A, B, C, D, E,$ and $F$ (not necessarily in that order) are sitting in $6$ chairs regularly placed around a round table. It is observed that:
$1$. $A$ is between $D$ and $F$.
$2$. $C$ is opposite to $D$.
$3$. $D$ and $E$ are not on neighbouring chairs.
Which one of the following must be true?

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$A, B, C, D, E,$ and $F$ (not necessarily in that order) are sitting in $6$ chairs regularly placed around a round table. It is observed that:$1$. $A$ is between $D$ and $F$.$2$. $C$ is opposite to $D$.$3$. $D$ and $E$ are not on neighbouring chairs.Which one of the following must be true?