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(D) Let the upward journey sequence be $1, 2, 3, 4, 5$. $D$ is the first stop in the downward journey,so $D$ is the $5^{th}$ stop in the upward journe

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$DEACB$

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(D) Let the upward journey sequence be $1, 2, 3, 4, 5$. $D$ is the first stop in the downward journey,so $D$ is the $5^{th}$ stop in the upward journey. $A$ and $E$ are not terminal stops,so they cannot be $1$ or $5$. $C$ is not the middle stop ($3^{rd}$ position). Let the upward sequence be $x_1, x_2, x_3, x_4, D$. $C$ comes twice as many stops before $D$ as $B$ comes after $A$. If $A$ is at $1$ and $B$ is at $2$,then $B$ is $1$ stop after $A$. So $C$ must be $2$ stops before $D$. If $D$ is $5$,$2$ stops before $D$ is $3$. So $C = 3$,but $C$ cannot be the middle stop. If $A$ is at $2$ and $B$ is at $4$,then $B$ is $2$ stops after $A$. So $C$ must be $4$ stops before $D$. If $D$ is $5$,$4$ stops before $D$ is $1$. So $C = 1$. Remaining stops $A, E, B$ are at $2, 3, 4$. Since $A=2, B=4$,then $E=3$. Upward sequence: $C, A, E, B, D$. Downward sequence is the reverse: $D, B, E, A, C$. Checking the options,$D, E, A, C, B$ is $DEACB$.

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