$_{Z}X^{M} + _{2}He^{4} \to _{15}P^{30} + _{0}n^{1}$. Then

  • A
    $Z = 12, M = 27$
  • B
    $Z = 13, M = 27$
  • C
    $Z = 12, M = 17$
  • D
    $Z = 13, M = 28$

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