$Nd$ $(Z = 60)$ is a member of group $3$ in the periodic table. An isotope of it is $\beta$-active. The daughter nuclei will be a member of Group $...$ ...

$A$ radioactive substance ${}_{88}X^{228}$ (Group $IIA$) emits $3 \alpha$ and $3 \beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?

$A$ radioactive substance $_{88}X^{228}$ $(IIA)$ emits $3$ $\alpha$ and $3$ $\beta$ particles to form $Y$. To which group of the long form of the periodic table does $Y$ belong?

$A$ nuclide of an alkaline earth metal undergoes radioactive decay by emission of two $\alpha$-particles in succession. The group of the periodic table to which the resulting daughter element would belong is $Group$ .......

$_{92}U^{235}$ belongs to group $III-B$ of the periodic table. If it loses one $\alpha$-particle,the new element will belong to group:

In the reaction $Po$ $\xrightarrow{-\alpha} Pb$ $\xrightarrow{-\beta} Bi$,if $Bi$ belongs to group $15$,to which group does $Po$ belong?