In the reaction Po xrightarrow{-alpha} Pb xri | vedclass

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(D) According to the group displacement law: $1$. Emission of an $\alpha$-particle decreases the atomic number by $2$,shifting the element two groups

Vedclass · Accepted Answer

$16$

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(D) According to the group displacement law: $1$. Emission of an $\alpha$-particle decreases the atomic number by $2$,shifting the element two groups to the left. $2$. Emission of a $\beta$-particle increases the atomic number by $1$,shifting the element one group to the right. Let the group of $Po$ be $G$. After $\alpha$-emission,the group of $Pb$ is $(G - 2)$. After $\beta$-emission from $Pb$,the group of $Bi$ is $(G - 2 + 1) = (G - 1)$. Given that $Bi$ belongs to group $15$,we have $G - 1 = 15$,which implies $G = 16$. Therefore,$Po$ belongs to group $16$.

In the reaction $Po$ $\xrightarrow{-\alpha} Pb$ $\xrightarrow{-\beta} Bi$,if $Bi$ belongs to group $15$,to which group does $Po$ belong?

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