Do $4, 10, 16, 22, \ldots$ form an $AP$? If they form an $AP,$ write the next two terms.
(A) We have $a_{2}-a_{1} = 10-4 = 6$.
$a_{3}-a_{2} = 16-10 = 6$.
$a_{4}-a_{3} = 22-16 = 6$.
Since the difference $a_{k+1}-a_{k}$ is constant for all $k$,the given list of numbers forms an $AP$ with the common difference $d = 6$.
The next two terms are:
$22 + 6 = 28$
$28 + 6 = 34$.
$a_{3}-a_{2} = 16-10 = 6$.
$a_{4}-a_{3} = 22-16 = 6$.
Since the difference $a_{k+1}-a_{k}$ is constant for all $k$,the given list of numbers forms an $AP$ with the common difference $d = 6$.
The next two terms are:
$22 + 6 = 28$
$28 + 6 = 34$.
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