Do $1, 1, 1, 2, 2, 2, 3, 3, 3, \ldots$ form an $AP$? If they form an $AP$,write the next two terms.
(NO) An arithmetic progression $(AP)$ is a sequence of numbers such that the difference between any two consecutive terms is constant.
Let the sequence be $a_1, a_2, a_3, a_4, \ldots = 1, 1, 1, 2, 2, 2, 3, 3, 3, \ldots$
Calculate the common difference $d$ between consecutive terms:
$d_1 = a_2 - a_1 = 1 - 1 = 0$
$d_2 = a_3 - a_2 = 1 - 1 = 0$
$d_3 = a_4 - a_3 = 2 - 1 = 1$
Since $d_1 = d_2 \neq d_3$,the difference between consecutive terms is not constant.
Therefore,the given sequence does not form an $AP$.
Let the sequence be $a_1, a_2, a_3, a_4, \ldots = 1, 1, 1, 2, 2, 2, 3, 3, 3, \ldots$
Calculate the common difference $d$ between consecutive terms:
$d_1 = a_2 - a_1 = 1 - 1 = 0$
$d_2 = a_3 - a_2 = 1 - 1 = 0$
$d_3 = a_4 - a_3 = 2 - 1 = 1$
Since $d_1 = d_2 \neq d_3$,the difference between consecutive terms is not constant.
Therefore,the given sequence does not form an $AP$.
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Similar Questions
Fill in the blanks in the following table,given that $a$ is the first term,$d$ is the common difference,and $a_{n}$ is the $n^{th}$ term of the $AP$:
$S.No.$ $a$ $d$ $n$ $a_{n}$ $(i)$ $7$ $3$ $8$ $...$ $(ii)$ $-18$ $...$ $10$ $0$ $(iii)$ $...$ $-3$ $18$ $-5$ $(iv)$ $-18.9$ $2.5$ $...$ $3.6$ $(v)$ $3.5$ $0$ $105$ $...$
| $S.No.$ | $a$ | $d$ | $n$ | $a_{n}$ |
| $(i)$ | $7$ | $3$ | $8$ | $...$ |
| $(ii)$ | $-18$ | $...$ | $10$ | $0$ |
| $(iii)$ | $...$ | $-3$ | $18$ | $-5$ |
| $(iv)$ | $-18.9$ | $2.5$ | $...$ | $3.6$ |
| $(v)$ | $3.5$ | $0$ | $105$ | $...$ |
Difficult
View SolutionFind the sum of first $22$ terms of an $AP$ in which $d=7$ and $22^{nd}$ term is $149$.
Medium
View SolutionFor the following $APs,$ write the first term and the common difference: $0.6, 1.7, 2.8, 3.9, \ldots$
Medium
View SolutionIn an $AP$ given $a=7$ and $a_{13}=35$,find $d$ and $S_{13}$.
Medium
View SolutionShow that $a_{1}, a_{2}, \ldots, a_{n}, \ldots$ form an $AP$ where $a_{n}$ is defined as $a_{n}=3+4 n$. Also,find the sum of the first $15$ terms.
Difficult
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