frac{2 tan 30^{circ}}{1+tan ^{2} 30^{circ}} = | vedclass

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Question

(B) We know that $	an 30^{\circ} = \frac{1}{\sqrt{3}}$.Substituting this value into the expression:$\frac{2 	an 30^{\circ}}{1+	an ^{2} 30^{\circ}}

Vedclass · Accepted Answer

$\sin 60^{\circ}$

Vedclass · Answer

(B) We know that $	an 30^{\circ} = \frac{1}{\sqrt{3}}$.Substituting this value into the expression:$\frac{2 	an 30^{\circ}}{1+	an ^{2} 30^{\circ}} = \frac{2(\frac{1}{\sqrt{3}})}{1+(\frac{1}{\sqrt{3}})^2}$$= \frac{\frac{2}{\sqrt{3}}}{1+\frac{1}{3}} = \frac{\frac{2}{\sqrt{3}}}{\frac{4}{3}}$$= \frac{2}{\sqrt{3}} 	imes \frac{3}{4} = \frac{6}{4\sqrt{3}} = \frac{3}{2\sqrt{3}} = \frac{\sqrt{3}}{2}$.Since $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,the correct option is $B$.

$\frac{2 \tan 30^{\circ}}{1+\tan ^{2} 30^{\circ}} = ?$

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