(D) Using the property of radicals $\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}$,we have:$\sqrt{10} \times \sqrt{15} = \sqrt{10 \times 15}$$= \sqrt{1

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(D) Using the property of radicals $\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}$,we have:$\sqrt{10} \times \sqrt{15} = \sqrt{10 \times 15}$$= \sqrt{150}$$= \sqrt{25 \times 6}$$= \sqrt{25} \times \sqrt{6}$$= 5 \sqrt{6}$Therefore,the correct option is $D$.