frac{sin 60^{circ} + cos 30^{circ}}{1 + sin 3 | vedclass

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Question

(D) આપણે ત્રિકોણમિતીય મૂલ્યો જાણીએ છીએ: $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,$\cos 30^{\circ} = \frac{\sqrt{3}}{2}$,$\sin 30^{\circ} = \frac{1}{2}$,

Vedclass · Accepted Answer

$\frac{\sqrt{3}}{2}$

Vedclass · Answer

(D) આપણે ત્રિકોણમિતીય મૂલ્યો જાણીએ છીએ: $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,$\cos 30^{\circ} = \frac{\sqrt{3}}{2}$,$\sin 30^{\circ} = \frac{1}{2}$,અને $\cos 60^{\circ} = \frac{1}{2}$.આ કિંમતોને પદાવલિમાં મૂકતા:$\frac{\sin 60^{\circ} + \cos 30^{\circ}}{1 + \sin 30^{\circ} + \cos 60^{\circ}} = \frac{\frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2}}{1 + \frac{1}{2} + \frac{1}{2}}$$= \frac{\frac{2\sqrt{3}}{2}}{1 + 1}$$= \frac{\sqrt{3}}{2}$

$\frac{\sin 60^{\circ} + \cos 30^{\circ}}{1 + \sin 30^{\circ} + \cos 60^{\circ}} = \dots$

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