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Question

(B) The mass of copper $(Cu)$ is $4 \ g$. The mass of the oxide formed is $5 \ g$.The mass of oxygen $(O)$ in the oxide is $5 \ g - 4 \ g = 1 \ g$.Acc

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(B) The mass of copper $(Cu)$ is $4 \ g$. The mass of the oxide formed is $5 \ g$.The mass of oxygen $(O)$ in the oxide is $5 \ g - 4 \ g = 1 \ g$.According to the law of equivalent proportions,the mass of an element that combines with $8 \ g$ of oxygen is its equivalent weight.Equivalent weight of $Cu = \frac{	ext{Mass of } Cu}{	ext{Mass of } O} 	imes 8 \ g$.Equivalent weight of $Cu = \frac{4 \ g}{1 \ g} 	imes 8 \ g = 32 \ g$.Thus,the equivalent weight of copper is $32$.

$4 \ g$ of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave $5 \ g$ of its oxide. The equivalent weight of copper is

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