(D) To find the $\text{l.c.m.}$ of $36$ and $94$,we first find their prime factorizations:$36 = 2^2 \times 3^2$$94 = 2 \times 47$The $\text{l.c.m.}$ i

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(D) To find the $\text{l.c.m.}$ of $36$ and $94$,we first find their prime factorizations:$36 = 2^2 \times 3^2$$94 = 2 \times 47$The $\text{l.c.m.}$ is the product of the highest power of each prime factor present in the numbers:$\text{l.c.m.} = 2^2 \times 3^2 \times 47$$\text{l.c.m.} = 4 \times 9 \times 47$$\text{l.c.m.} = 36 \times 47 = 1692$

Class 10 Mathematics Real Numbers Mix Examples - Real Numbers

Easy

$\text{l.c.m.} (36, 94) = \dots$

A
$36$
B
$94$
C
$3694$
D
$1692$

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Mix Examples - Real Numbers

Find the $g.c.d.$ (Greatest Common Divisor) of $75$ and $243$ using Euclid's division algorithm.

Medium

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Express $96$ as a product of prime factors.

Easy

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Find the $\text{g.c.d.}$ (Greatest Common Divisor) of $196$ and $38220$ using Euclid's division algorithm.

Easy

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According to Euclid's division lemma,for $a$ and $5$,if $a = 5q + r$ is unique,then $r = \ldots$ is not possible.

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Prove that $6^{n}$ cannot end with the digit $0$ for any natural number $n \in N$.

Medium

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$\text{l.c.m.} (36, 94) = \dots$

Similar Questions

Find the $g.c.d.$ (Greatest Common Divisor) of $75$ and $243$ using Euclid's division algorithm.

Express $96$ as a product of prime factors.

Find the $\text{g.c.d.}$ (Greatest Common Divisor) of $196$ and $38220$ using Euclid's division algorithm.

According to Euclid's division lemma,for $a$ and $5$,if $a = 5q + r$ is unique,then $r = \ldots$ is not possible.

Prove that $6^{n}$ cannot end with the digit $0$ for any natural number $n \in N$.

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