angle ACD is an exterior angle of Delta ABC. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the Exterior Angle Theorem of a triangle,the measure of an exterior angle of a triangle is equal to the sum of the measures of its tw

Vedclass · Accepted Answer

$54$

Vedclass · Answer

(A) According to the Exterior Angle Theorem of a triangle,the measure of an exterior angle of a triangle is equal to the sum of the measures of its two interior opposite angles.In $\Delta ABC$,$\angle ACD$ is the exterior angle at vertex $C$.Therefore,$\angle ACD = \angle A + \angle B$.Given that $\angle ACD = 122^{\circ}$ and $\angle A = 68^{\circ}$.Substituting the values,we get: $122^{\circ} = 68^{\circ} + \angle B$.Solving for $\angle B$: $\angle B = 122^{\circ} - 68^{\circ} = 54^{\circ}$.Thus,$\angle B = 54^{\circ}$.

$\angle ACD$ is an exterior angle of $\Delta ABC$. If $\angle ACD = 122^{\circ}$ and $\angle A = 68^{\circ}$,then $\angle B = \ldots$ (in $^{\circ}$)

Similar Questions

$\angle X$ and $\angle Y$ are supplementary angles. If $\angle X : \angle Y = 23 : 13$,then find $\angle X$ and $\angle Y$.

In the figure,$\angle 1 = 60^{\circ}$ and $\angle 6 = 120^{\circ}$. Show that the lines $m$ and $n$ are parallel.

In the given figure,$AB \parallel DE$ and $BC \parallel EF$. Prove that $\angle ABC + \angle DEF = 180^{\circ}$.

Two lines $l$ and $m$ are perpendicular to the same line $n$. Are $l$ and $m$ perpendicular to each other? Give reason for your answer.

An angle has a measure equal to $\frac{5}{4}$ of the measure of its complementary angle. Find the measure of that angle. (in $^o$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module