In the figure,$\angle 1 = 60^{\circ}$ and $\angle 6 = 120^{\circ}$. Show that the lines $m$ and $n$ are parallel.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) We are given that $\angle 1 = 60^{\circ}$ and $\angle 6 = 120^{\circ}$.
From the figure,$\angle 5$ and $\angle 6$ form a linear pair.
Therefore,$\angle 5 + \angle 6 = 180^{\circ}$.
Substituting the value of $\angle 6$,we get $\angle 5 + 120^{\circ} = 180^{\circ}$.
$\angle 5 = 180^{\circ} - 120^{\circ} = 60^{\circ}$.
Now,we observe that $\angle 1 = 60^{\circ}$ and $\angle 5 = 60^{\circ}$.
Thus,$\angle 1 = \angle 5$.
Since $\angle 1$ and $\angle 5$ are corresponding angles and they are equal,the lines $m$ and $n$ must be parallel.

Explore More

Similar Questions

If one of the two angles of a linear pair has measure $x^{\circ},$ then the other angle has measure of $\ldots \ldots . .$

Bisectors of angles $B$ and $C$ of a triangle $ABC$ intersect each other at the point $O$. Prove that $\angle BOC = 90^{\circ} + \frac{1}{2} \angle A$.

Difficult
View Solution

If the measure of an acute angle is $x^{\circ}$,find the difference of the measure of its supplementary angle and complementary angle. (in $^{\circ}$)

Prove that the sum of angles of any convex quadrilateral is $360^{\circ} .$

An angle which is greater than $180^{\circ}$ but less than $360^{\circ}$ is called a $\ldots \ldots \ldots .$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo