x = dots is a solution of the quadratic equat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the solution of the quadratic equation $x^{2} + 7x + 12 = 0$,we factorize the quadratic expression.We look for two numbers whose product i

Vedclass · Accepted Answer

$-3$

Vedclass · Answer

(B) To find the solution of the quadratic equation $x^{2} + 7x + 12 = 0$,we factorize the quadratic expression.We look for two numbers whose product is $12$ and whose sum is $7$.These numbers are $3$ and $4$.So,the equation can be written as $x^{2} + 3x + 4x + 12 = 0$.Grouping the terms,we get $x(x + 3) + 4(x + 3) = 0$.Factoring out $(x + 3)$,we get $(x + 3)(x + 4) = 0$.Setting each factor to zero,we get $x + 3 = 0$ or $x + 4 = 0$.Thus,$x = -3$ or $x = -4$.Comparing this with the given options,$-3$ is a solution.

$x = \dots$ is a solution of the quadratic equation $x^{2} + 7x + 12 = 0$.

Similar Questions

If one of the roots of $2x^{2}-5x+k=0$ is $\frac{7}{2}$,then $k=$ .............

If the roots of the quadratic equation $3x^{2} + 2\sqrt{5}x - 5 = 0$ exist,find them using the method of completing the square.

Obtain the roots of the following equation using the method of 'completing the square': $3y^{2} + 7y - 20 = 0$.

Solve the following quadratic equation using the quadratic formula,if the equation has a solution in $R$: $3x^2 + 5\sqrt{2}x - 2 = 0$.

The value of the discriminant $D$ of the quadratic equation $x^{2} + 5x + 1 = 0$ is $\ldots \ldots \ldots \ldots .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module