(1+tan ^{2} theta)(1-cos ^{2} theta) = dots | vedclass

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(B) We know the trigonometric identities: $1 + 	an^{2} 	heta = \sec^{2} 	heta$ and $1 - \cos^{2} 	heta = \sin^{2} 	heta$. Substituting these into

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$	an ^{2} 	heta$

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(B) We know the trigonometric identities: $1 + 	an^{2} 	heta = \sec^{2} 	heta$ and $1 - \cos^{2} 	heta = \sin^{2} 	heta$. Substituting these into the expression: $(1 + 	an^{2} 	heta)(1 - \cos^{2} 	heta) = \sec^{2} 	heta \cdot \sin^{2} 	heta$. Since $\sec 	heta = \frac{1}{\cos 	heta}$,we have: $\sec^{2} 	heta \cdot \sin^{2} 	heta = \frac{1}{\cos^{2} 	heta} \cdot \sin^{2} 	heta = \frac{\sin^{2} 	heta}{\cos^{2} 	heta} = 	an^{2} 	heta$.

$(1+\tan ^{2} \theta)(1-\cos ^{2} \theta) = \dots$

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