CH_3-CH=CH-CH(OH)-CH_3 xrightarrow{text{Jones | vedclass

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(B) The Jones reagent ($CrO_3$ in $H_2SO_4/H_2O$) is a strong oxidizing agent used for the oxidation of alcohols.It oxidizes primary alcohols to carbo

Vedclass · Accepted Answer

$CH_3CH=CHCOCH_3$

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(B) The Jones reagent ($CrO_3$ in $H_2SO_4/H_2O$) is a strong oxidizing agent used for the oxidation of alcohols.It oxidizes primary alcohols to carboxylic acids and secondary alcohols to ketones.The given substrate is $pent-3-en-2-ol$,which is an allylic secondary alcohol.Jones reagent oxidizes the secondary alcohol group $(-CH(OH)-)$ to a ketone group $(-C=O)$ without affecting the carbon-carbon double bond $(C=C)$ under standard conditions.Therefore,the reaction is:$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{Jones \ reagent} CH_3-CH=CH-COCH_3$The product $X$ is $pent-3-en-2-one$ $(CH_3CH=CHCOCH_3)$.

$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{\text{Jones reagent}} X$,
Product $X$ is

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$CH_3-CH=CH-CH(OH)-CH_3 \xrightarrow{\text{Jones reagent}} X$,Product $X$ is