A and B are two wires. The radius of A is twi | vedclass

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(B) Stress is defined as the force applied per unit area,given by the formula: $	ext{Stress} = \frac{F}{A} = \frac{F}{\pi r^2}$.Since the load $F$ is

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Four times that on $A$

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(B) Stress is defined as the force applied per unit area,given by the formula: $	ext{Stress} = \frac{F}{A} = \frac{F}{\pi r^2}$.Since the load $F$ is the same for both wires,the stress is inversely proportional to the square of the radius: $	ext{Stress} \propto \frac{1}{r^2}$.Given that the radius of wire $A$ is twice that of wire $B$,we have $r_A = 2r_B$,which implies $\frac{r_A}{r_B} = 2$.Comparing the stress on wire $B$ $(S_B)$ and wire $A$ $(S_A)$:$\frac{S_B}{S_A} = \left( \frac{r_A}{r_B} ight)^2 = (2)^2 = 4$.Therefore,the stress on $B$ is $4$ times the stress on $A$ $(S_B = 4S_A)$.

$A$ and $B$ are two wires. The radius of $A$ is twice that of $B$. They are stretched by the same load. Then the stress on $B$ is

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