A ray of light enters from a medium with refr | vedclass

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(D) According to Snell's Law of refraction,the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the rati

Vedclass · Accepted Answer

$\frac{n_2}{n_1}$

Vedclass · Answer

(D) According to Snell's Law of refraction,the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive index of the second medium to the refractive index of the first medium.Mathematically,this is expressed as: $n_1 \sin 	heta_1 = n_2 \sin 	heta_2$.Rearranging the terms to find the ratio $\frac{\sin 	heta_1}{\sin 	heta_2}$,we get:$\frac{\sin 	heta_1}{\sin 	heta_2} = \frac{n_2}{n_1}$.

$A$ ray of light enters from a medium with refractive index $n_1$ into a medium with refractive index $n_2$. If the angle of incidence is $\theta_1$ and the angle of refraction is $\theta_2$,then $\sin \theta_1 / \sin \theta_2 = \dots$

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