[Fe(CN)_6]^{4-}; [Fe(CN)_6]^{3-}; [Ti(CN)_6]^ | vedclass

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(C) $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $d^6$,$CN^-$ is a strong field ligand,so $t_{2g}^6 e_g^0$. Diamagnetic.$[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$,$CN^-

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$2$

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(C) $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $d^6$,$CN^-$ is a strong field ligand,so $t_{2g}^6 e_g^0$. Diamagnetic.$[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$,$CN^-$ is a strong field ligand,so $t_{2g}^5 e_g^0$. Paramagnetic ($1$ unpaired electron).$[Ti(CN)_6]^{3-}$: $Ti^{3+}$ is $d^1$,so $t_{2g}^1 e_g^0$. Paramagnetic ($1$ unpaired electron).$[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $d^8$,$CN^-$ is a strong field ligand,so $dsp^2$ hybridization. Diamagnetic.$[Co(CN)_6]^{3-}$: $Co^{3+}$ is $d^6$,$CN^-$ is a strong field ligand,so $t_{2g}^6 e_g^0$. Diamagnetic.Therefore,the number of paramagnetic complexes is $2$.

$[Fe(CN)_6]^{4-}$; $[Fe(CN)_6]^{3-}$; $[Ti(CN)_6]^{3-}$; $[Ni(CN)_4]^{2-}$; $[Co(CN)_6]^{3-}$
Among the given complexes,the number of paramagnetic complexes is .... .

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$[Fe(CN)_6]^{4-}$; $[Fe(CN)_6]^{3-}$; $[Ti(CN)_6]^{3-}$; $[Ni(CN)_4]^{2-}$; $[Co(CN)_6]^{3-}$Among the given complexes,the number of paramagnetic complexes is .... .