$\lim _{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}$ का मान ज्ञात कीजिए।

  • A
    $14$
  • B
    $7$
  • C
    $14 \sqrt{2}$
  • D
    $7 \sqrt{2}$

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Similar Questions

$\mathop {\lim }\limits_{x \to \pi /4} \frac{{\sqrt 2 \cos x - 1}}{{\cot x - 1}} = $

$\mathop {\lim }\limits_{\alpha \to \pi /4} \frac{{\sin \alpha - \cos \alpha }}{{\alpha - \frac{\pi }{4}}} = $

$\lim _{x \rightarrow \frac{\pi}{2}}\left(\frac{1}{\left(x-\frac{\pi}{2}\right)^2} \int_{x^3}^{\left(\frac{\pi}{2}\right)^3} \cos \left(t^{1/3}\right) d t\right)$ का मान ज्ञात कीजिए।

$\lim _{x \rightarrow 0} \frac{2 \sin x-\sin 2 x}{x^3}$ का मान ज्ञात कीजिए।

यदि $\lim _{x}$ ${\rightarrow 1} \frac{(5 x+1)^{1 / 3}-(x+5)^{1 / 3}}{(2 x+3)^{1 / 2}-(x+4)^{1 / 2}}=\frac{m \sqrt{5}}{n(2 n)^{2 / 3}}$,जहाँ $\operatorname{gcd}(m, n)=1$,तो $8 m+12 n$ का मान ज्ञात कीजिए।

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