[Fe(CN)_{6}]^{3-} is an inner orbital complex | vedclass

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Question

(D) The complex is $[Fe(CN)_{6}]^{3-}$.$Fe$ is in the $+3$ oxidation state,so its electronic configuration is $3d^{5}$.$CN^{-}$ is a strong field liga

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) The complex is $[Fe(CN)_{6}]^{3-}$.$Fe$ is in the $+3$ oxidation state,so its electronic configuration is $3d^{5}$.$CN^{-}$ is a strong field ligand,which causes pairing of electrons in the $d$-orbitals.For an octahedral complex,the $d$-orbitals split into $t_{2g}$ and $e_{g}$ sets.The $5$ electrons occupy the $t_{2g}$ orbitals as $(t_{2g}^{5} e_{g}^{0})$.The crystal field stabilization energy $(CFSE)$ is calculated as:$CFSE = n(t_{2g}) 	imes (-0.4 \Delta_{o}) + n(e_{g}) 	imes (0.6 \Delta_{o})$$CFSE = 5 	imes (-0.4 \Delta_{o}) + 0 	imes (0.6 \Delta_{o}) = -2.0 \Delta_{o}$.Thus,the value is $2$.

$[Fe(CN)_{6}]^{3-}$ is an inner orbital complex. Ignoring the pairing energy,the value of crystal field stabilization energy for this complex is $(-)\;\dots \;\Delta_{o}$.

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