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Question

(B) The complexes are:$A: [Ni(H_{2}O)_{2}(en)_{2}]^{2+}$$B: [Ni(H_{2}O)_{4}(en)]^{2+}$$C: [Ni(en)_{3}]^{2+}$$en$ (ethylenediamine) is a stronger field

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$C > A > B$

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(B) The complexes are:$A: [Ni(H_{2}O)_{2}(en)_{2}]^{2+}$$B: [Ni(H_{2}O)_{4}(en)]^{2+}$$C: [Ni(en)_{3}]^{2+}$$en$ (ethylenediamine) is a stronger field ligand $(SFL)$ compared to $H_{2}O$.According to the spectrochemical series,the crystal field splitting energy $(\Delta_{0})$ increases as the number of strong field ligands increases.In complex $C$,there are $3$ $en$ ligands.In complex $A$,there are $2$ $en$ ligands.In complex $B$,there is $1$ $en$ ligand.Therefore,the order of crystal field splitting energy $(\Delta_{0})$ is $C > A > B$.Since the energy absorbed $(E = h
u = \Delta_{0})$ is directly proportional to the splitting energy,the order of energy absorbed is $C > A > B$.

The order of energy absorbed,which is responsible for the color of the following complexes,is:

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