In tetrahedral coordination complexes,what is | vedclass

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(D) In a tetrahedral crystal field,the $d$-orbitals split into two sets: the $e$ set ($d_{x^2-y^2}$ and $d_{z^2}$) and the $t_2$ set ($d_{xy}$,$d_{yz}

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$d_{x^2-y^2} \cong d_{z^2} < d_{xy} \cong d_{yz} \cong d_{xz}$

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(D) In a tetrahedral crystal field,the $d$-orbitals split into two sets: the $e$ set ($d_{x^2-y^2}$ and $d_{z^2}$) and the $t_2$ set ($d_{xy}$,$d_{yz}$,and $d_{xz}$).Because the ligands approach from the corners of a tetrahedron,the $t_2$ orbitals are closer to the ligands than the $e$ orbitals.Therefore,the $t_2$ orbitals have higher energy than the $e$ orbitals.The correct order of energy is $e < t_2$,which corresponds to $(d_{x^2-y^2} \cong d_{z^2}) < (d_{xy} \cong d_{yz} \cong d_{xz})$.

In tetrahedral coordination complexes,what is the order of energy levels of $d$-orbitals during crystal field splitting?

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