RNH_2 reacts with C_6H_5SO_2Cl (Hinsberg reag | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Primary amine $(RNH_2)$ reacts with $C_6H_5SO_2Cl$ to form $N$-alkylbenzenesulfonamide $(RNHSO_2C_6H_5)$.$2$. This product contains an acidic

Vedclass · Accepted Answer

$R-NH-SO_2-C_6H_5$ (precipitate)

Vedclass · Answer

(C) $1$. Primary amine $(RNH_2)$ reacts with $C_6H_5SO_2Cl$ to form $N$-alkylbenzenesulfonamide $(RNHSO_2C_6H_5)$.$2$. This product contains an acidic hydrogen attached to the nitrogen atom,so it dissolves in aqueous $KOH$ to form a water-soluble potassium salt,$RN(K^+)SO_2C_6H_5$.$3$. Upon acidification of this solution,the potassium salt is converted back into the insoluble $N$-alkylbenzenesulfonamide $(RNHSO_2C_6H_5)$,which appears as a precipitate.

$RNH_2$ reacts with $C_6H_5SO_2Cl$ (Hinsberg reagent) in aqueous $KOH$ to give a clear solution. On acidification,a precipitate is obtained which is due to the formation of:

Similar Questions

Correct sequence of reagents for the conversion shown in the image is $-$

What are $X$ and $Y$ in the following reactions?

Select the incorrect reaction among the following:

What is the role of pyridine in the acylation reaction of amines?

The correct order of basic strength for the given nitrogen atoms $(x)$,$(y)$,and $(z)$ is $-$

Vedclass Test Series

Exam Paper Generator

Online Exam Module