Correct sequence of reagents for the conversion shown in the image is $-$

  • A
    $OH^-$ or $H^+$,$HNO_3 / H_2SO_4$ at $288 \ K$,$(CH_3CO)_2O / \text{Pyridine}$
  • B
    $(CH_3CO)_2O / \text{Pyridine}$,$OH^-$ or $H^+$,$HNO_3 / H_2SO_4$ at $288 \ K$
  • C
    $HNO_3 / H_2SO_4$ at $288 \ K$,$(CH_3CO)_2O / \text{Pyridine}$,$OH^-$ or $H^+$
  • D
    $(CH_3CO)_2O / \text{Pyridine}$,$HNO_3 / H_2SO_4$ at $288 \ K$,$OH^-$ or $H^+$

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Similar Questions

The correct order of basic strength of the following amines is

Identify substrate $A$ in the following conversion.
$A + \underset{\text{(excess)}}{CH_3 I} \xrightarrow{\Delta} C_2 H_5(CH_3)_3 N^+ I^-$

Account for the following:
$(i)$ $pK_{b}$ of aniline is more than that of methylamine.
$(ii)$ Ethylamine is soluble in water whereas aniline is not.
$(iii)$ Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
$(iv)$ Although amino group is $o-$ and $p-$ directing in aromatic electrophilic substitution reactions,aniline on nitration gives a substantial amount of $m$-nitroaniline.
$(v)$ Aniline does not undergo Friedel-Crafts reaction.
$(vi)$ Diazonium salts of aromatic amines are more stable than those of aliphatic amines.
$(vii)$ Gabriel phthalimide synthesis is preferred for synthesising primary amines.

The major product $B$ in the following reaction sequence is:
$CH_3-CH_2-CH(CH_3)-CONH_2$ $\xrightarrow{Br_2/KOH, \Delta} (A)$ $\xrightarrow{(1) CH_3I (excess), (2) AgOH/\Delta} (B)$

The increasing order of diazotisation of the following compounds is:

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