The IUPAC name of the following compound is: | vedclass

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(D) The principal functional group is the ketone group,so the carbon atom of the carbonyl group is assigned position $1$.To determine the numbering,we

Vedclass · Accepted Answer

$5$-hydroxycyclohex-$2$-en-$1$-one

Vedclass · Answer

(D) The principal functional group is the ketone group,so the carbon atom of the carbonyl group is assigned position $1$.To determine the numbering,we follow the rule of lowest locants for substituents and multiple bonds.Starting from the carbonyl carbon as $C_1$,if we number clockwise,the double bond starts at $C_2$ and the hydroxyl group is at $C_5$.If we number counter-clockwise,the double bond starts at $C_5$ and the hydroxyl group is at $C_3$.Comparing the locant sets $(2, 5)$ and $(3, 5)$,the set $(2, 5)$ is preferred because it provides a lower number at the first point of difference.Therefore,the correct $IUPAC$ name is $5$-hydroxycyclohex-$2$-en-$1$-one.

The $IUPAC$ name of the following compound is:

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