The IUPAC name of the given compound is: | vedclass

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(B) $1$. Identify the principal functional group: The $-OH$ group has the highest priority,so the parent chain is a cyclobutene derivative named as cy

Vedclass · Accepted Answer

$4-$Methylcyclobut$-2-$en$-1-$ol

Vedclass · Answer

(B) $1$. Identify the principal functional group: The $-OH$ group has the highest priority,so the parent chain is a cyclobutene derivative named as cyclobut$-2-$en$-1-$ol.$2$. Numbering the ring: The carbon attached to the $-OH$ group is assigned position $1$. The numbering should proceed towards the double bond to give it the lowest possible locant.$3$. Assigning locants: If we number clockwise starting from the $-OH$ carbon,the double bond starts at position $2$ and the methyl group is at position $4$. If we number counter-clockwise,the double bond starts at position $3$ and the methyl group is at position $2$. Following the lowest locant rule for the double bond,we choose the clockwise numbering.$4$. Final Name: The substituent is a methyl group at position $4$. Thus,the correct $IUPAC$ name is $4-$methylcyclobut$-2-$en$-1-$ol.

The $IUPAC$ name of the given compound is:

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