$5 \%$ of the power of a $100 \, W$ bulb is converted to visible radiation. The average intensity of visible radiation at a distance of $10 \, m$ from the bulb is .......... $W/m^2$.

  • A
    $\frac{5}{2 \pi (10)^2}$
  • B
    $\frac{5}{4 \pi (10)^2}$
  • C
    $\frac{5}{\pi (10)^2}$
  • D
    $\frac{5}{8 \pi (10)^2}$

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The electric field intensity produced by the radiation coming from a $100 \, W$ bulb at a distance of $3 \, m$ is $E$. The electric field intensity produced by the radiation coming from a $60 \, W$ bulb at the same distance is $\sqrt{\frac{x}{5}} E$. The value of $x$ is ......... .

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