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Question

(B) The correct matches based on the genetic material content are as follows:$1$. Bacteriophage $\phi 	imes 174$ contains $5386$ nucleotides $(P-I)$.

Vedclass · Accepted Answer

$(P-I), (Q-II), (R-IV), (S-III)$

Vedclass · Answer

(B) The correct matches based on the genetic material content are as follows:$1$. Bacteriophage $\phi 	imes 174$ contains $5386$ nucleotides $(P-I)$.$2$. Bacteriophage lambda contains $48502$ base pairs $(bp)$ $(Q-II)$.$3$. Escherichia coli $(E. coli)$ contains $4.6 	imes 10^6 \, bp$ $(R-IV)$.$4$. Human haploid $DNA$ content is $3.3 	imes 10^9 \, bp$ $(S-III)$.Therefore,the correct matching sequence is $(P-I), (Q-II), (R-IV), (S-III)$.

Column-$I$	Column-$II$
$P$. Bacteriophage $\phi \times 174$	$I$. $5386$ nucleotides
$Q$. Bacteriophage lambda	$II$. $48502 \, bp$
$R$. Escherichia coli	$III$. $3.3 \times 10^9 \, bp$
$S$. Human haploid $DNA$	$IV$. $4.6 \times 10^6 \, bp$

Match the following columns:

Column-$I$ Column-$II$

$P$. Bacteriophage $\phi \times 174$ $I$. $5386$ nucleotides

$Q$. Bacteriophage lambda $II$. $48502 \, bp$

$R$. Escherichia coli $III$. $3.3 \times 10^9 \, bp$

$S$. Human haploid $DNA$ $IV$. $4.6 \times 10^6 \, bp$

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Match the following columns: Column-$I$ Column-$II$ $P$. Bacteriophage $\phi \times 174$ $I$. $5386$ nucleotides $Q$. Bacteriophage lambda $II$. $48502 \, bp$ $R$. Escherichia coli $III$. $3.3 \times 10^9 \, bp$ $S$. Human haploid $DNA$ $IV$. $4.6 \times 10^6 \, bp$