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(B) At resonance,the impedance $Z$ of an $LCR$ circuit is equal to the resistance $R$,i.e.,$Z = R$.The current amplitude $I$ at resonance is given by

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double

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(B) At resonance,the impedance $Z$ of an $LCR$ circuit is equal to the resistance $R$,i.e.,$Z = R$.The current amplitude $I$ at resonance is given by $I = \frac{V}{R}$,where $V$ is the peak voltage.When the resistance $R$ is halved,the new resistance becomes $R' = \frac{R}{2}$.The new current amplitude $I'$ becomes $I' = \frac{V}{R'} = \frac{V}{R/2} = 2 \left( \frac{V}{R} \right) = 2I$.Therefore,the current amplitude becomes double the original value.

An $LCR$ circuit is at resonance for a capacitor $C$,inductance $L$,and resistance $R$. If the value of the resistance is halved while keeping all other parameters the same,the current amplitude at resonance will be:

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