In an $LCR$ series $AC$ circuit at resonance,the value of the power factor will be . . . . . . .

An $AC$ voltage $V = 220 \sin(2 \times 10^3 t) \text{ V}$ is applied to a series $LCR$ circuit. The current amplitude in this circuit is: (Given: $L = 10 \text{ mH}$, $C = 25 \mu\text{F}$, $R = 100 \Omega$) (in $\text{ A}$)

What is resonance in an $LCR$ series circuit?

In a series $L-C-R$ circuit,$C = 10^{-11} \, F$,$L = 10^{-5} \, H$,and $R = 100 \, \Omega$. When a constant $D.C.$ voltage $E$ is applied to the circuit,the capacitor acquires a charge of $10^{-9} \, C$. The $D.C.$ source is replaced by a sinusoidal voltage source in which the peak voltage $E_0$ is equal to the constant $D.C.$ voltage $E$. At resonance,the peak value of the charge acquired by the capacitor will be:

Power delivered by the $ac$ source of the circuit becomes maximum when

The reading of the ammeter in the circuit shown will be: (in $A$)