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(C) The reaction of ethylamine $(CH_3CH_2NH_2)$ with $NaNO_2 / HCl$ followed by water produces ethanol,nitrogen gas,and water:$CH_3CH_2NH_2 + NaNO_2 +

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$45$

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(C) The reaction of ethylamine $(CH_3CH_2NH_2)$ with $NaNO_2 / HCl$ followed by water produces ethanol,nitrogen gas,and water:$CH_3CH_2NH_2 + NaNO_2 + HCl ightarrow CH_3CH_2OH + N_2(g) + NaCl + H_2O$From the stoichiometry,$1 \ mole$ of ethylamine $(45 \ g)$ produces $1 \ mole$ of $N_2$ gas.At $STP$,$1 \ mole$ of gas occupies $22.4 \ L$.Given that $2.24 \ L$ of $N_2$ gas is evolved,the number of moles of $N_2$ is:$n = \frac{2.24 \ L}{22.4 \ L/mol} = 0.1 \ mol$Since $1 \ mole$ of ethylamine produces $1 \ mole$ of $N_2$,$0.1 \ mol$ of ethylamine is required.The mass of $0.1 \ mol$ of ethylamine is:$Mass = 0.1 \ mol 	imes 45 \ g/mol = 4.5 \ g$We need to express $4.5 \ g$ as $X 	imes 10^{-1} \ g$,so $X = 45$.

$X \ g$ of ethylamine is subjected to reaction with $NaNO_2 / HCl$ followed by water; evolved dinitrogen gas which occupied $2.24 \ L$ volume at $STP$. $X$ is . . . . . . $\times 10^{-1} \ g$.

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