CuSO_4 decolourises on addition of KCN,the pr | vedclass

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Question

(C) When $KCN$ is added to $CuSO_4$,initially $Cu(CN)_2$ is formed,which is unstable.$Cu^{2+} + 2CN^{-} \rightarrow Cu(CN)_2$This $Cu(CN)_2$ immediate

Vedclass · Accepted Answer

$Cu^{2+}$ gets reduced to form $\left[Cu(CN)_4\right]^{3-}$

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(C) When $KCN$ is added to $CuSO_4$,initially $Cu(CN)_2$ is formed,which is unstable.$Cu^{2+} + 2CN^{-} \rightarrow Cu(CN)_2$This $Cu(CN)_2$ immediately decomposes to form $CuCN$ and cyanogen gas $(CN)_2$.$2Cu(CN)_2 \rightarrow 2CuCN + (CN)_2$Further,$CuCN$ reacts with excess $KCN$ to form the stable complex $K_3[Cu(CN)_4]$.$CuCN + 3KCN \rightarrow K_3[Cu(CN)_4]$Therefore,the final product is the complex $\left[Cu(CN)_4\right]^{3-}$.

$CuSO_4$ decolourises on addition of $KCN$,the product is

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