${\left( \frac{\cos \theta + i\sin \theta}{\sin \theta + i\cos \theta} \right)^4}$ equals

  • A
    $\sin 8\theta - i\cos 8\theta$
  • B
    $\cos 8\theta - i\sin 8\theta$
  • C
    $\sin 8\theta + i\cos 8\theta$
  • D
    $\cos 8\theta + i\sin 8\theta$

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If $1, \omega, \omega^2$ are the cube roots of unity,then $\frac{1}{1+2 \omega}+\frac{1}{2+\omega}-\frac{1}{1+\omega}=$

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